Regex problem

String:
/ a_xxxx / b_xxxx / c_xxx I need to check out
xxx, where xxx can be any character , a, b, c the position may not be fixed , or no example:
/ a_111/b_222/c_333
/ a_111/b_222
/ b_222/a_111/c_333

Will this regex should be how to write
------ Solution --------------------------- -----------------

String s = "/a_xxxx/b_xxxx/c_xxx";
  		Pattern p = Pattern.compile("\\d+");//定义规则
  		String str[] = p.split(s);//进行拆分
  		for (int i = 0; i < str.length; i++) {
  			System.out.println(str[i]);
  		}

------ Solution ----------------- ---------------------------

	public static void main(String[] args) {
  		String str = "/a_111/b_222/c_333xsdsd";
  		Pattern pattern = Pattern.compile("[abc]_([^/]+)");
  		Matcher m = pattern.matcher(str);
  		while(m.find()) {
  			System.out.println(m.group(1));
  		}
  	}

------ Solution ------- -------------------------------------
private static void mytest6 () ; {
String str = "/ a_sfsdf/b_werwer/c_333";
Pattern p = Pattern.compile ("[abc] _ (. *?) (([^ /]) $ | /)");
Matcher m = p.matcher (str);
while (m.find ()) {
if (m.group (3) == null) {
System.out.println (m.group (1));
} else {
System.out.println (m.group (1) + m.group (3));
}

}
}
------ Solution ----------------------------------- ---------
top look under the third floor ,
should be no problem
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not mean that. By matcher first find, and then group got , I wrote a little behind do not know how to write.

  String str = "/a_111/b_222/c_333";
  Pattern pattern = Pattern.compile("/a_(?<a>.+?)(/|$)");
  Matcher matcher = pattern.matcher(str);
  System.out.println(matcher.find());
  System.out.println(matcher.group("a"));
  

The main problems are two, one is a, b, c the relative position determination , and the other b, c may not .
If the string yes yes / a_111/b_222/c_333, I want to wait until 111,222,333 ;
If the string yes yes / a_111/c_333, I want to wait until 111,333 ;
If the string yes yes / b_222/a_111/c_333, I want to wait until 222,111,333;
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Why must a regular , first splist ("/"), in the split ("_" ;) not Well
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this good point

  private static void mytest6() {
  		String str = "/a_xxxx/c_xxx/b_2234";
  		Pattern p = Pattern.compile("[abc]_(.*?)($|/)");
  		Matcher m = p.matcher(str);
  		while (m.find()) {
  				System.out.println(m.group(1));
  		}
  	}
  

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Thank you very much , just needs changed, the string should look like this:
/ a/111/b/222/c/333
Here 111,222,333 may be alphanumeric ;
Further a, b, c may be text that a combination of number of letters , but it is fixed.

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string might be:
/ title/111/content/222
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	public static void main(String[] args) {
  		String str = "/title/111/content/222";
  		Pattern pattern = Pattern.compile("[a-z]+/([^/]+)");
  		Matcher m = pattern.matcher(str);
  		while(m.find()) {
  			System.out.println(m.group(1));
  		}
  	}

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thanks for the ladies and gentlemen , I know how to write.

  Pattern pattern = Pattern.compile("/(title|content)/([^/]+)");
  Matcher matcher = pattern.matcher(str);
  while(matcher.find()){
  	System.out.println(matcher.group(2));
  }
  

very, very grateful .