JAVA language to write a filter <a href = ........ </ a> regex

Requirement is put a label to filter out . For example: I was hyperlinked text lovers . put " hyperlinked text " are removed . Discuss , thank you ~
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see your label whether a canonical form , and if you do not consider the space ( for example, does not appear xxx ), can do:

String[] href = {
                  "go<a href=u.php?action=show&uid=122113 target=_blank>超链接文本</a>od",
                  "go<a href=u.php?action=show&uid=122113 target=_blank>超链接文本</a>od<a href></a>",
          };
          for (String h : href) {
              System.out.println(h.replaceAll("<a[^>]+>[^<]*</a>", ""));
          }

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In fact, you can give an example of a little more appropriate . .
html.repaceAll ("? s) ", "");
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replaceAll (" "," ");
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	static void func4()
  	{
  		String str="one <a href=u.php?action=show&uid=122113 target=_blank>超链接文本</a>  two <a> adfadf </a> Three";
  		System.out.println("before:-----------------\n"+str);
  		String regex="<\\s*a.*?/a\\s*>";
  		str=str.replaceAll(regex, "");
  		System.out.println("after:-----------------\n"+str);
  	}