JAVA how to convert the contents of a byte array into a picture

I received a picture from the terminal byte array containing the data , how to be able to convert it into a picture of it ?
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using FileOutputStream, the following code , but I do not do effectively verified

  
  import java.io.*;
  /**
   模拟一个jpeg位图到byte[]
   */
  class Image2Buff
  {
  	static byte[] image2Bytes(String imgSrc) throws Exception
  	{
  		FileInputStream fin = new FileInputStream(new File(imgSrc));
  		//可能溢出,简单起见就不考虑太多,如果太大就要另外想办法，比如一次传入固定长度byte[]
  		byte[] bytes  = new byte[fin.available()];
  		//将文件内容写入字节数组，提供测试的case
  		fin.read(bytes);
  		fin.close();
  		return bytes;
  	}
  }
  
  class Buff2Image
  {
  	/**
  	 @param b 传入的byte
  	 @param tagSrc 目标文件名
  		
  	 */
  	static void buff2Image(byte[] b,String tagSrc) throws Exception
  	{
  		FileOutputStream fout = new FileOutputStream(tagSrc);
  		//将字节写入文件
  		fout.write(b);
  		fout.close();
  	}
  }
  
  //本质上实现了copy 命令
  public class ImageBufTest
  {
  	public static void main(String[] args) throws Exception
  	{
  		//先模拟一个图形byte[]
  		byte[] b = Image2Buff.image2Bytes("c:/1.jpg");
  		//存为文件
  		Buff2Image.buff2Image(b,"c:/test.jpg");
  
  		System.out.println("Hello World!");
  	}
  }
  
  

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but my byte array is obtained from the network, not read directly from a now have Jpg file.
I pass the byte array object after following fout , JPG files obtained can not be displayed when you open the preview ! ! ! !

FileOutputStream fout = new FileOutputStream (tagSrc); / / bytes written to the file fout.write (b);
fout.close ();

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lacks distinction , since it is a byte [], you can use FileOutputStream

If you do not get the picture , it should be byte [] not read it ? Here to read your forum avatar by URL way
also get on the network , the essence is still the same thing ,

  
  import java.io.*;
  import java.net.*;
  /**
   模拟一个jpeg位图到byte[]
   */
  class Image2Buff
  {
  	static byte[] image2Bytes(String imgSrc) throws Exception
  	{
  		FileInputStream fin = new FileInputStream(new File(imgSrc));
  		//可能溢出,简单起见就不考虑太多,如果太大就要另外想办法，比如一次传入固定长度byte[]
  		byte[] bytes  = new byte[fin.available()];
  		//将文件内容写入字节数组，提供测试的case
  		fin.read(bytes);
  		fin.close();
  		return bytes;
  	}
  
  	//从网上读取图片地址，存入本地
  	static byte[] image2BytesFromURL(String address) throws Exception
  	{
  		URL url = new URL(address);
  		InputStream is = url.openStream();
  		byte[] bytes  = new byte[is.available()];
  		//将文件内容写入字节数组，提供测试的case
  		is.read(bytes);
  		return bytes;
  	}
  
  }
  
  class Buff2Image
  {
  	/**
  	 @param b 传入的byte
  	 @param tagSrc 目标文件名
  		
  	 */
  	static void buff2Image(byte[] b,String tagSrc) throws Exception
  	{
  		FileOutputStream fout = new FileOutputStream(tagSrc);
  		//将字节写入文件
  		fout.write(b);
  		fout.close();
  	}
  }
  
   
  public class ImageBufTest
  {
  	public static void main(String[] args) throws Exception
  	{
  		//先模拟一个图形byte[]
  		byte[] b = Image2Buff.image2Bytes("c:/1.jpg");
  		//存为文件
  		Buff2Image.buff2Image(b,"c:/test.jpg");
  		//通过url 读取图片得到bytes,复制你的头像到本地
  		byte[] b2 = Image2Buff.image2BytesFromURL("http://avatar.profile.csdn.net/D/C/3/1_hjx_code.jpg");
  		Buff2Image.buff2Image(b2,"c:/test2.jpg");
  		System.out.println("Hello World!");
  	}
  }
  
  

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landlord copy of this document is the same with nothing more than read write process flow streams . From the network constantly reading the image bytes written to the image file contents continuously until the completion of the read and write it wants
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ah , your code does work , but also very standardized.
may really I did not get to the cause of all the bytes of data .
thank you.

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brother upstairs test code does not know not, tell the landlord Tieshanglai
upstairs code image2Bytes is obviously wrong
you return but only one has a length byte array readable stream that white is an all zero byte array
not the contents of the stream , and then you put the empty array write files , apparently failed .

landlord should do
byte [] buf = new byte [in.available ()]; data stream that is used to keep it in just the first composed entirely of 0
int i = 0;
while ((i = in.read (buf))! = -1) {/ / this time is the flow of the specific content of buf
out.write (buf, 0, i);
}
out.close ();