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Great God helped me see why the int type exceeds the maximum range, the output will eventually become zero, rather than negative ?
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65536 * 65536 binary outcome take 32 is a 0
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+ +
Yes, originally 0 , is not beyond the range of 0
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32 th power . Take the low 32-bit result is 0


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65536 * 65536 = 4294967296, its binary representation is :
1 0000 0000 0000 0000 0000 0000 0000 0000 There are 33 , int type to take the low 32 , which is 32 0 ; .

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pro, help me to explain a specific point? ? The concept is not very clear ah brother
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65536 hex is 3CB0, two multiply finish is how variable 0 Yeah