This argu represents the current root directory.
then run when the current project , located in the root directory is where ?
where the tomcat ? In the bin it?
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tomcat webapp directory below
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C: \ Program Files \ Apache Software Foundation \ Tomcat 6.0 \ webapps
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TOMCAT under webapps inside
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.....
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positive solutions
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in tomcat webapps directory server directory you installed under
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can get by System.getProperty ("user.dir").
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TOMCAT under --------------------- ------------------
project alone on the right -properties- right side there is a location that is
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wrong. Servlet running when the current directory is where ? Not a bin next , nor is there webapps solve ah.
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eclips is IDE, the development environment is not a WEB server how to run the project ? I said do not understand .
tomcat server.xml which is running the project configuration .
<Host name="localhost" appBase="webapps"
unpackWARs="true" autoDeploy="true"
xmlValidation="false" xmlNamespaceAware="false">
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In the ECLIPSE project to build and run the project in the servlet file , this time in the current directory where ?
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ECLIPSE how to run servlet
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Run on server.. . . . .
when running String argu = ".";
argu directory where ?
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when running JAVA file. This argu refers to the current project directory . That means when running the web project where is it .
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not that directory. . String argu = "."
this path argu represents is which. Relative path
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limited comprehension can not understand sorry
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how nobody knew what I was in eclipse, run a web project upload control results should be I do not know where the root directory of the project can not upload . . . . Anybody know what I should add upload folder to the file folder can receive it . . . . . . The book says is the root directory
who will question if the release in the tomcat is running directly in the eclipse . . . . I can not find the
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